In an A. P. sum of three consecutive terms is 18 and their product is 192,find the rerms
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a - d +a + a +d = 18
3 a = 18
a = 18/3
a = 6
[a-d][a][a+d] = 192
[6-d][6][6+d] =192
6[36-d²] =192
36-d² = 32
d² = 4
d =2 or d= -2
the terms are 8 , 6 and 4
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