Question

In an A.P T16=47,T31=92 then find T27

Answer 1

Answer:-30

Step-by-step explanation:

T=A+(N-1)D..STANDARD FORMULA

47 = A+46 D...1

92= A+30 D..2

16 D=- 45   (BY SUBTRACTING 1 AND 2)

D=-45/16=-2.8125

SUBST'N D=2.8125 IN (1) WE GET,

A=47+129.375=-82.375

A=-82

T27= -82+26*2=-30

T27= -30

Step-by-step explanation:

Answer 2

Answer:

=80

Step-by-step explanation:

t31=92 we can write it as a+30d=92 ,,t16=47 we can write it as a+15d=47 ,,by subtracting both of them we get 15d=45 means d=3 ,when we substituite d value in a+30d=92 ,a+30×3=92,a+90=92,a=92-90=2. tn=a+(n-1)d,t27=2+(27-1)3,2+26×3=80