Question

In an A.P the 10th term is 46 sum of 5the and 7the term is 52. find the A.P​

Answer 1

Step-by-step explanation:

For an A.P., let a be the first term and d be the common difference. t10 = 46, t5 + t7 = 52 …[Given] Since, tn = a + (n – 1)d

∴ t10 = a + (10 – 1)d

∴ 46 = a + 9d i. e. a + 9d = 46 …(i)

Also, t5 + t7 = 52

∴ a + (5 – 1)d + a + (7 – 1)d = 52

∴ a + 4d + a + 6d = 52

∴ 2a + 10d = 52 ∴ 2 (a + 5d) = 52

∴ a + 5d = 52/2

∴ a + 5d = 26 …(ii)

Subtracting equation (ii) form (i), we get Substituting d = 5 in equation (ii),

a + 5(5) = 26

∴ a + 25 = 26

∴ a = 26 – 25 = 1

t1 =

a = 1 t2 = t1 + d = 1 + 5 = 6

t3 = t2 + d = 6 + 5 = 11

t4 = t3 + d = 11 + 5 = 16 The required is 1 6 11 16

Answer 2

Answer:

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