Question

in an A. P the 11th term is 38 and the 16th term is 73 . the 31st term of the A. p​

Answer 1

Answer:

Hey buddy here is ur answer..

Step-by-step explanation:

11th term(a+10d) = 38

16th term(a+15d) = 73

On solving the two equations,

-5d = -35

Therefore, d=7 .

And, a = -32 .

So, 31st term(a+30d) = 178 .

Hope it helps u!!

Take care:):)

Answer 2

Given, a11 = 38 and a16 = 73 We know that an = a + (n – 1)d Hence, a11 = a + 10d = 38 And, a16 = a + 15d = 73 Subtracting 11th term from 16th term, we get following: a + 15d – a – 10d = 73 – 38 Or, 5d = 35 Or, d = 7 Substituting the value of d in 11th term we get; a + 10 x 7 = 38 Or, a + 70 = 38 Or, a = 38 – 70 = - 32 Now 31st term can be calculated as follows: a31 = a + 30d = - 32 + 30 x 7 = - 32 + 210 = 178