In an A. P the 1st term is -4 the last term is 29 and sum of all term is 150 ,find the common difference
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a=-4,l=29,sum=150.
sn=n/2(a+l)
150= n/2(-4+29)
150=n/2×25
300/25=n
n=12 .
l=a+(n-1)×d
29=-4+(11d)
23=11d
d=23/11 answer
sn=n/2(a+l)
150= n/2(-4+29)
150=n/2×25
300/25=n
n=12 .
l=a+(n-1)×d
29=-4+(11d)
23=11d
d=23/11 answer
arsh103:
its wrong
what. what is the answer
Answered by
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a=(-4)
l =29
sum =150
S= n/2(a+l)
n/2(-4+29)=150
n/2(25)=150
n(25)=300
n=300/25
n=12
S=n/2 (2a+(n-1)d)
=12/2(2(-4)+11d)
6(-8+11d)=150
-48+66d=150
66d=198
d=198/66
d=3
l =29
sum =150
S= n/2(a+l)
n/2(-4+29)=150
n/2(25)=150
n(25)=300
n=300/25
n=12
S=n/2 (2a+(n-1)d)
=12/2(2(-4)+11d)
6(-8+11d)=150
-48+66d=150
66d=198
d=198/66
d=3
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