Question

In an a.p , the first term is 2 and the sum of first five terms is 5 , then the 31th term is?

Answer 1

ANSWER:

31th term = -13

TO FIND:

31th term

GVEN:

a = 2

a + a + d + a + 2d + a + 3d + a 4d = 5

5a + 10d = 5

EXPLANATION:

5a + 10d = 5

Substitute a = 2

10 + 10d = 5

10d = -5

d = -5/10

d = -0.5

$a_n$ = a + (n-1)d

$a_{31}$ = 2 + (30) -0.5

$a_{31}$ = 2 - 15

$a_{31}$ = -13

31th term = -13

Answer 2

Answer:

In an A.P. the first term is 2 and the sum of the first five terms is one-fourth of the next five terms

so 31 = -13

First Term of A.P. = a = 2

Sum of first n terms =

Where n is the number of terms

a is the first term

d is the common difference

We are given that the sum of the first five terms is one- fourth of the sum of the next- five terms.

Substitute n 20

Step-by-step explanation:

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