In an A.p. the first term is 22, nth term is -11 and the sum to first n terms is 66. Find n and d, the common difference.
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2
Answer:
12
Step-by-step explanation:
a = 22
tn = -11
sn = 66
tn = a + (n-1)d
-11= 22 + (n-1)d
(n-1)d = -33
sn = n/2 {2a + (n-1)d}
66 = n/2 (44-33)
66 = 11n/2
n = 66 × 2/11
= 6 × 2 = 12
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