In an A.P the first term is 25 and the last term is -17 and the sum of n terms is 132.Find n and the common difference.
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Answer is in the above given attachment
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Step-by-step explanation:
The formula is
Sn= (1st term + Last term/ 2) × n
132= 25+(-17)/2 × n
132= 25-17/2 × n
132= 8/2 × n
132= 4n
So n=132÷4
= 33
To find common difference d=
tn=a+(n-1)d [according to the formula]
-17=25+(33-1)d
-17=25+32d
-17-25=32d
-42=32d
-42/32=d
-21/16=d
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