in an A.P the sum of the three terms is 24, and their is 480, write the three terms of A.P .
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Let the numbers be a-d, a and a+d
According to first condition,
a - d + a + a + d = 24
=> 3a = 24
=> a = 8
According to second condition,
( a - d) (a) (a +d) = 504
=> a ( a^2 - d^2) = 504
=> 8 [ (8)^2 - (d)^2] = 504
=> 64 - d^2 = 63
=> d^2 = 1
=> d = 1
First number = 8 - 1 = 7
Second number = 8
Third number = 8 +1 = 9
Answered by
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Answer:
Let the numbers be a-d, a and a+d
According to first condition,
a - d + a + a + d = 24
=> 3a = 24
=> a = 8
According to second condition,
( a - d) (a) (a +d) = 504
=> a ( a^2 - d^2) = 504
=> 8 [ (8)^2 - (d)^2] = 504
=> 64 - d^2 = 63
=> d^2 = 1
=> d = 1
First number = 8 - 1 = 7
Second number = 8
Third number = 8 +1 = 9
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