Question

In an A.P the sum of three consecutive terms is 30 and their product is 360. Find the terms. (terms are in ascending order) *​

Answer 1

Answer:

the 3 consecutive terms are 4,10,14

Step-by-step explanation:

let let 3 consecutive terms be a-d ,a ,a+d

some are three consecutive terms is 30

then 3A = 30 which implies a = 10

product of three consecutive terms is 360 then (a-d )xa x (a + d)

which implies a²-d² x a= 360

a²-d²=360/10

100-d²=36

-d²=-64

d=6 which implies

a-d=4

a=6

a+d=14

therefore the three consecutive terms are 4,6,14