Question

In an A.P the sum of three terms is 27 and their sum of squares is 293. Find the three terms

Answer 1

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Step-by-step explanation:

Answer 2

Step-by-step explanation:

Let the three terms be a-d , a , a+d

Now,

sum of three terms = 27

a-d + a + a +d = 27

3a = 27

a = 9

A/Q,

sum of squares = 293

(a-d)² + a² + (a+d)² = 293

a² + d² - 2ad + 81 + a² + d² +2ad = 293

81 + 81 +81 + 2d² = 293

2d²= 50

d²= 25

d = ±5

Therfore a = 9

d = ±5

The A.P may be 4 , 9 , 14......

or. 14, 9, 4......