in an A.P the third and sixth term are 1 and -11 .find the sum of the first 32 terms.
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According to given sum,
let first term be a and common difference be d
third term=a+(n-1)d
a+2d=1............(.i )
sixth term = a+(n-1)d
a+5d=-11.......(.ii )
subtracting equation i from ii. we get
3d=-12
d=-4
substitute the value of d in equation i. we get
a+2 (-4)=1
a=1+8=9
32 term =a+31d
=9+31×-4
=-115.
:-)hope it helps u.
let first term be a and common difference be d
third term=a+(n-1)d
a+2d=1............(.i )
sixth term = a+(n-1)d
a+5d=-11.......(.ii )
subtracting equation i from ii. we get
3d=-12
d=-4
substitute the value of d in equation i. we get
a+2 (-4)=1
a=1+8=9
32 term =a+31d
=9+31×-4
=-115.
:-)hope it helps u.
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