Question

In an A.P, three times of 3rd term is equal to eight times of the 8th term, then find 11th term? ​

Answer 1

Answer:

Step-by-step explanation:

Answer 2

The 11th term is 0

Step-by-step explanation:

Formula of nth term :$A_n=a+(n-1)d$

Where A_n = nth term

a = first term

n = No. of term

d = common difference

Substitute n = 3

$A_3=a+(3-1)d=a+2d$

Substitute n = 8

$A_8=a+(8-1)d=a+7d$

In an A.P, three times of 3rd term is equal to eight times of the 8th term

So, $3(a+2d)=8(a+7d)$

$3a+6d=8a+56d$

$-50d=5a$

-10d=a

Substitute n = 11

$a_{11}=a+(11-1)d=-10d+10d=0$

Hence The 11th term is 0

#Learn more;

If five times the 5th term of an A.P. is equal to eight times its 8th term,then show that 13th term is zero

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