In an A.P. values of 10th term and 22nd
term is 33 and - 3 respectively, find 4th
term of the A.P.
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Answer:
GIVEN
10TH TERM =33
a+9d=33.
a=33-9d
22ND TERM =-3
a+21d=-3
put the value of a from above
we get
d=-3
now put the value of d in
a=33-9d
we get a=60
TO FIND 4th TERM
a+3d=60+3(-3)
=51ans
4TH TERM OF AN AP IS 51
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