Question

In an △ABC, AB=AC and ∠C = 80°. Find each of the equal angles.​

Answer 1

Answer:

∆ABC=180°

=> angle A = angle B = angle C

=> A+B+C=180°

=> A+B+80°=180°

=> A+B=180°-80°

=> A+B=100°

let angle A and angle B be x and x

so,

=>x+x=100°

=>2x=100°

=>x=100°/2=50°

Therefore,the three angles measure 50°,50° and 80°

Answer 2

Answer:

ΔABC AB=AC

<A+<B+<C=180°

<A+<B+80°=180°

<A+<B=180°-80°

<A+<B=100

<A=50°

<B=50°