Question

In an ac circuit containing resistance only, E and I are given by E = 200 sin (200)t volt and = 100 sin (200)t ma. The power dissipated in the circuit is​

Answer 1

Answer:

Considering the given equation for V and I,  = 100V,  = 100A and 

Considering the given equation for V and I,  = 100V,  = 100A and then,  and 

Considering the given equation for V and I,  = 100V,  = 100A and then,  and Now, Power dissipated in the circuit is given by P = 

Considering the given equation for V and I,  = 100V,  = 100A and then,  and Now, Power dissipated in the circuit is given by P = =  = 2500W

Answer 2

Given: voltage, E = 200Sin(200)t V

           current, I = 100Sin(200)t ma

To find: Power dissipated in the circuit.

Solution: Power dissipated = Vrms × Irms × CosФ

Vrms is the voltage, Irms is the current, and CosФ is the phase difference.

Here, Vrms = 200V

        , Irms = 100 ma

        , Phase difference = zero

Power dissipated = 200 × 100 × Cos0° × 10⁻³

                             = 20 Watts

Therefore, the power dissipated is 20 Watts.

• The power dissipated is the rate at which energy is lost due to resistive elements.
• Alternating current (AC) is an electric current that periodically reverses direction and changes its magnitude continuously with time in contrast to direct current (DC) which flows only in one direction.
• RMS is the root mean square of the ac circuit.