Question

In an AC circuit, only a resistor of resistance 15
Q is present. If voltage applied is V = 150sin(50t)
volt then rms current is
(1) 52 A
(2) 5 A
(3) 10 A
(4) 10/2 A​

Answer 1

Answer:

5✓2A

Explanation:

THE end current is peak value/✓2

voltage amplitude= current amplitude x resistance

Answer 2

Answer:

The rms current in the circuit is $\frac{10}{\sqrt{2} }$ . None of the options are correct.

Explanation:

The waveform in the question is of the form,

$V=V_0sin\omega t$     (1)

By comparing equation (1) with the equation in question we get;

V₀=150volt

ω=50

The rms current is given as,

$I=\frac{I_0}{\sqrt{2} }$      (2)

Where,

I=rms current

I₀=peak current

And the peak current can be calculated as,

$I=\frac{V}{R}$       (3)

Where,

V₀=peak voltage

R=resistance of the circuit=15Ω    (given)

By substituting the required values in equation (3) we get;

$I=\frac{150}{15}=10A$       (4)

Now by substituting the value of I₀ in equation (2) we get;

$I=\frac{10}{\sqrt{2} }$

Hence, the rms current in the circuit is $\frac{10}{\sqrt{2} }$. None of the options are correct.