Question

in an ac circut current log v bypi/2 identify the circut​

Answer 1

Answer:

Given that,

Phase =

2

π

If,

V=V

0

sinωt

We know that,

q=CV

q=CV

0

sinωt

Now, the current

I=

dt

dq

I=

dt

d(CV

0

sinωt)

I=ωCV

0

cosωt

I=ωCV

0

sin(ωt+

2

π

)

Hence, the current is ωCV

0

sin(ωt+

2

π

)