Environmental Sciences, asked by vishakhamore144, 1 month ago

In an activated sludge process 200 mg/lit is influent B. O. D., 20 mg/l is effluent BOD ,then efficiency of BOD removal is

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Answered by bannybannyavvari

1

Explanation:

activated sludge plant is to treat 10000 m3/d industrial wastewater ( BOD5 = 1200 mg/L; BOD effluent = 100 mg ...

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