In an acute angle ∆ABC if sin2(A+B-C)=1 and tan (B+C-A)=√3,then find the value of A,B,C
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the value of A is60
Bis 75
C is 45
Bis 75
C is 45
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Hi Mate ! ! !
We know that sum of angles of a trangle is = 180
A + B + C = 180...... equation 1
Sin2 ( A + B - C ) = Sin ( 90 )
because sin ( 90 ) = 1
A + B - C = 45 ..... equation 2
Tan ( B + C - A ) = Tan (60)
because Tan (60 ) = √3
B + C - A = 60 ...... equation 3
Now solve these equation to get value of A , B and C
We know that sum of angles of a trangle is = 180
A + B + C = 180...... equation 1
Sin2 ( A + B - C ) = Sin ( 90 )
because sin ( 90 ) = 1
A + B - C = 45 ..... equation 2
Tan ( B + C - A ) = Tan (60)
because Tan (60 ) = √3
B + C - A = 60 ...... equation 3
Now solve these equation to get value of A , B and C
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