In an acute angle ABC. S is any point on BC, Prove that AB+BC+CA>2AS
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In △ABS:AB+BS > AS.......(1)
In △ACS:AC+CS > AS..(2)
Equating(1)and(2):=
AB+BS+AC+CS > AS+AS
=AB+BC+CA>2AS
Hence Proved!
In △ACS:AC+CS > AS..(2)
Equating(1)and(2):=
AB+BS+AC+CS > AS+AS
=AB+BC+CA>2AS
Hence Proved!
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