in an acute angle triangle ABC if Sin (A + B - C) is equal to 1 /2 and cos( b + c - A) is equal to 1/root 2 find Angle A Angle B and angle C
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Answered by
3
Answer:
A=67.5
B=37.5
C=75
Step-by-step explanation:
Process is in picture
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Answered by
0
Answer:
Step-by-step explanation:
Sin(A+B-C) =sin30
Cos(B+c-a) =cos45
A+B-C=30... 1
B+C-a=45.... 2
ADD 1,2
2B=75
B=75/2
A+B+C=180
A+C=180-32.5
A+C=147.5.. 3
C-A=12.5.. 4
ADD3, 4
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