Math, asked by sahayasajithp, 10 months ago

In an acute angle triangle ABC, sin (A + B - C) = ½, cot (A - B + C) = 0 and cos (B
+C – A) =1/2. What are the values of A, B, and C?

Answers

Answered by harshitha200611
3

a + b - c = 30

a - b + c = 45

b + c - a = 60

Solve this three equ. to get the ans.

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