Question

in an acute angled triangle abc if cos(A+B-C =1/√2 and sin (b+c-a) =√3/2 the find a b c​

Answer 1

Answer:

Since the measures of these acute angles of a right triangle add to 90º, we know these acute angles are complementary. ∠A is the complement of ∠B, and ∠B is the complement of ∠A. The sine of any acute angle is equal to the cosine of its complement. The cosine of any acute angle is equal to the sine of its complement.