Question

In an acute angled triangle ABC , S is any point on BC .prove that AB +BC+CA>2AS .
plz solve it fast !!!!! plzz is there anyone intelligent enough !!!!!!! am giving 16 point ...... one to answer it first will get the brainliest answer !!!

Answer 1

$\text{In} \ \triangle ABS:\\AB + BS \ \textgreater \ AS.......(1)\\\\In \ \triangle ACS:\\AC+CS\ \textgreater \ AS.......(2)\\\\ Equating (1) and (2):\\=AB + BS + AC + CS\ \textgreater \ AS + AS\\=AB+BC+CA \ \textgreater \ 2AS\\Hence \ Proved!$

Answer 2

Hello friend
_____________________________________________________________

To prove :- AB + BC + CA > 2AS

Proof :- In triangle ABS,

AB + BS > AS ------------- Eq(1)

Now , In triangle ACS,

AC + CS > AS -------------Eq(2)

Now , from Eq (1) & (2) , we get

AB + BS + AC + CS > AS + AS

AB + BC + CA > 2AS ( BS + CS = BC )

HENCE PROVED
________________________________________________________

Hope it will help u