Question

In an acute triangle abc , if sin (a+b-c)=1/2 and cos (b+c-a)=1/root2 . find angle a b c

Answer 1

sin (a + b - c) = 1/2
a+b-c=30------(1)
cos (b+c-a) = 1/root2
b+c-a = 45------(2)
(2)-(1) 
b+c-a-a-b+c = 45 - 30
c - a = 15
b+c-a=45
b + 15 = 45
b=30