Question

in an alloy of bronze and silver, the ratio of their mass is 5:7. if the alloy has 35 gm of silver, find the weight of bronze present in the alloy. ​

Answer 1

Answer:

25 gm

Step-by-step explanation:

If 7 parts = 35

SO, 1 part =35/7

= 5

So, 5 part = 5*5

= 25

Answer 2

Answer:

Weight of bronze = 25 gm

Step-by-step explanation:

Weight = mass × gravitation

W = mg

mass of bronze : mass of silver = 5 : 7

$\frac{mass of bronze}{mass of silver} = \frac{5}{7}$

$\frac{m_{1}}{m_{2} } = \frac{5}{7}$

$\frac{m_{1}g}{m_{2}g } = \frac{5}{7}$

$\frac{W_{1}}{W_{2} } = \frac{5}{7} = \frac{25}{35}$

So, if weight of silver is 35 gm, then the weight of bronze = 25 gm.