In an alloy, the ratio of copper and zinc is 5:2. If 12 lbs of pure zinc is added to the alloy, the composition changes to 5:4, How much zinc (in lbs) was initially present in the alloy?
Answers
Given info : In an alloy, the ratio of copper and zinc is 5:2. If 12 lbs of pure zinc is added to the alloy, the composition changes to 5:4.
To find : How much zinc (in lbs) was initially present in the alloy ?
solution : let the proportionality constant is x
initial amount of copper = 5x
initial amount of zinc = 2x
final amount of copper = 5x
final amount of zinc = 2x + 12
a/c to question,
5x/(2x + 12) = 5/4
⇒4x = 2x + 12
⇒x = 6
so initial amount of zinc = 2x = 2 × 6 = 12 lbs
Therefore 12 lbs zinc was initially present in the alloy.
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