Question

In an alloy , the ratio of copper and zinc is 5 :2. If 12 lbs of pure zinc is added to the alloy , the composition changes to 5/4 . How much zinc (in ) was initially present in the alloy ?​

Answer 1

Answer:

Amount of copper =

7

5

×17.5kg=12.5kg

Amount of zinc =17.5kg−12.5kg=5kg.

Now, the amount of zinc =(5+1.25)kg

=6.25kg.

∴Required ratio=12.5:6.25=

6.25

12.5

=

625

1250

=

1

2

=2:1

Step-by-step explanation:

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Answer 2

Given :- In an alloy , the ratio of copper and zinc is 5 :2. If 12 lbs of pure zinc is added to the alloy , the composition changes to 5/4 . ?

To Find :- How much zinc (in ) was initially present in the alloy ?

Answer :-

Let us assume that, in alloy initially we have, 5x lbs copper and 2x lbs zinc .

so,

→ 5x/(2x + 12) = 5/4

→ 20x = 10x + 60

→ 20x - 10x = 60

→ 10x = 60

→ x = 6 .

then,

→ Initial quantity of zinc = 2x = 2 * 6 = 12 lbs (Ans.)

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