In an annual function, there were stalls of different games. In a game, 5 black, 10 red an20 white balls are mixed together and kept in an urn. * 10 was the ticket for each player to take one chance to take out a ball.person getting a black ball would win 20 ,those getting red ball would get 5 rs and those getting a white ball would get nothing . bindiya played the games 10 times and she got B,W,W,R,W,B,W,R,R ,W DID SHE WIN OR LOSE And by how much
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Bindiya played the games 10 times and she got,
B W W R W B W R R W
10 × 10 = Rs. 100 is spent by Bindiya
In a game, 5 black, 10 red and 20 white balls are mixed together and kept in an urn.
10 was the ticket for each player to take one chance to take out a ball.
person getting a black ball would win 20,
those getting red ball would get 5 rs and
those getting a white ball would get nothing
2 - Black = 2 × 20 = 40
3 - Red = 3 × 5 = 15
5 - White = 5 × 0 = 0
Total amount received by Bindiya = Rs 55
Bindiya spent Rs 100 & she received Rs 55
Therefore, the amount lost by Bindiya is
= Rs 100 - Rs 55
= Rs 45
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