Question

In an ap, 1/a is first term and 1/b is the fifth term, then the common difference of the ap is
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Answer 1

Answer :

$\frac{a-b}{4ab}$

Solution :

Given :

In an AP,

First term = 1/a

Fifth term = 1/b

Common difference = $\frac{a_{n} - a_{m}}{n - m}$

= $\frac{ \frac{1}{b} - \frac{1}{a} }{5 - 1}$

= $\frac{ \frac{a - b}{ab} }{5 - 1}$

= $\frac{a-b}{4ab}$