In an AP:
1 given a =5, d = 3, a = 50, find n and S
22 what
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Answer:
n=16 and S(22)=374
a(n)=50
a=5
d=3
a(n)=a+(n-1)d
50=5+(n-1)3
45=(n-1)3
n-1=45/3=15
n=15+1=16
S(n)=n/2[2a+(n-1)d]
S(22)=11[10+(21)3]=11[10+24]=11(34)=374
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