in an ap 16 14 12 the sum of how many terms are 60 why we get double answer explain?
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Given:- a=16 , a2=14 , Sn=60
{we have to find n(number of terms)}
we know that,
d=a2-a=14-16=(-2)
(.•. Sn=n/2{2a+(n-1)d}
60=n/2{2×16+(n-1)(-2)}
120=n(32-2n+2)
120=n(34-2n)
120=34n-2n²
2n²-34n+120=0
n²-17n+60=0
(.:. it is a quadratic equation n should have two values)
i.e., n²-5n-12n+60=0
n(n-5)-12(n-5)=0
(n-12) (n-5)=0
n=12 or n=5. :°_°:Ans
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