in an AP 1st term is 2,coomon difference is 8 .sum of nth term is 90.Find the number o terms and nth term
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Step-by-step explanation:
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Step-by-step explanation:
a= 2
D=8
Sn = 90
n/2 {2a+(n-1)D} =90
Putting values
n{4+8n-8} =180
8n^2 - 4n - 180= 0
2n^2 - n - 45 = 0
2n^2 - 10n + 9n - 45 =0
2n( n-5) +9( n-5) =0
(2n-9)(n-5)=0
2n-9 =0 or n-5=0
n=9/2 or n=5
9/2 is rejected
n=5
An = a+(n-1)D
= 2+(5-1)8
=2+32 = 34
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