Question

In an AP 1st term is 5 and last term is 302, d=3 then find value of n

Answer 1

Answer:

$\rm 100$

Step-by-step explanation:

We know that,

$\boxed{\rm a_n = a+(n-1)d}$

$\rm 302 = 5+(n-1)3$

$\rm 302-5 = (n-1)3$

$\rm 297 = (n-1)3$

$\rm \dfrac{297}{3} = (n-1)$

$\rm n-1=99$

$\rm n=99+1$

$\rm n=100$