Question

in an ap 3 8 13 dotdotdot 253 find the 20 term from the last​

Answer 1

We have,I = Last term =253

and,

D=Commerce difference =8 - 3

= 5

therefore,20th term from the end

=1 - (20 -1)d

=1 - 19d

=253 - 19 × 5

=253 - 95

=158

p

Answer 2

Given,

3,8,13........it is an AP

a=3

d=5

tn=253

n=?

tn=a+(n-1)d

253=3+5n-5

253=-2+5n

5n=253+2

5n=255

n=51

the last term is 51th

the second last is 50th

the third last is 49th

so the 20th from last term=(51-19)th

=32th

tn=a+(n-1)d

t32=3+(32-1)×5

=3+31×5

=3+155

t32=158

The 20th from the last term is an AP is 158.

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