In an AP 3rd term is 8 and the 9th term is 2 more than the 3 types of 3 Rd term then prove that the sum of 19 the term is 551
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3rd term=a+2d=8....(1)
9th term=a+8d
A.T.Q
a+8d=2+3(a+2d)
By solving,
a+8d=2+3a+6d
8d-6d+a-3a=2
-2a+2d=2
-a+d=1....(2)
From (1)...(2)
3d=9
d=3 and a=2
Now,sum of 19 terms is
n/2(2a+(n-1)d)
19/2(2×2+18×3)
19/2(58)
=19×29=551
Hence proved!!
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