In an AP 3rd term is 8 and the 9th term is 2 more then the 3types of 3rd term then prove that the sum of 19th term is 551
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Given,a+2d=8, a+8d=3(a+2d)+2
a+2d=8,. 2a+2d=2
2d=8-a,. 2a+8-a=2
a= -6
d=14
sum of 19 terms=19/2(2(-6)+18(14))
=19/2(240)=228
wwwmanjesh5:
Sir I don't understand plz explain Briefly in each step and working plz sir
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hey mate here is the answer for you.
note that Sn= n/2[2a+(n-1)d].
please mark it as brainliest.
note that Sn= n/2[2a+(n-1)d].
please mark it as brainliest.
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i hope you understood that what i posted
Yes sir thanking you sir I understand completely thank you very much sir
you mean mam
Okk mam thanks
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