in an AP 5th term is 21 and 2nd term is 9 find the 25th term of AP
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Answer:
Step-by-step explanation:
given,
5th term of AP = 21
9th term of AP = 9
nth term = a + (n-1) d
21 = a + (5-1) d
21= a+ 4d eq1
9 = a+ (9-1)d
9 = a+ 8d eq2
subtract eq2 from eq1
12= -4 d
d= -3
substitue d value in eq1
21 = a + 4(-3)
21 = a-12
a= 33
now,
25th term = 33 + 24*-3
= 33 - 72
= -39
hope it helps
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