Question

in an AP 6,9,12,15 find the value of 12 terms
​

Answer 1

Answer:

39.

Step-by-step explanation:

Given that,:

$a_{1} = 6$

$a_{2} = 9$

$d = a_{2} - a_{1}$

$d = 9 - 6$

$d = 3$

$n = 12$

To find:

$a_{12}$

Proof:

We know that,

$a_{n} = a_{1} + (n - 1)d$

On substituting the given values,

$a_{12} = 6 + (12 - 1)3$

$a_{12} = 6 + 11(3)$

$a_{12} = 6 + 33$

$a_{12} = 39$

Therefore, the 12th term of the AP is 39.

Hope it helps you.

Good Luck.