Question

in an ap 6 times the 6th is equal to the 11 times the 11th term find its 17th term

Answer 1

6(a+5d)=11(a+10d)
-5a=110d-30d

5a+80d=0
a+16d=0..i. e., seventeenth term=0

Answer 2

Answer:

17th term of A.P is 0

Step-by-step explanation:

Given in an A.P 6 times the 6th is equal to the 11 times the 11th term

we have to find its 17th term.

Let the first term of AP is a and common difference d

The 6th term of A.P is a+5d

The 11th term of A.P is a+10d

As in an A.P 6 times the 6th tem is equal to the 11 times the 11th term

6(a+5d)=11(a+10d)

6a+30d=11a+110d

5a+80d=0

a+16d=0

a+(17-1)d=0

$a_{17}=0$

Hence, 17th term of A.P is 0