in an Ap a=2 d=8 sn=90 find n
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Given :-
- a = 2
- d = 8
- Sn = 90
To Find :-
- n
Solution :-
Sn = n/2 [2a + (n - 1)d]
➜ 90 = n/2 [2 × 2 + (n - 1) × 8]
➜ 90 = n/2 [5 + 8n - 8]
➜ 90 = n/2 [8n - 4]
➜ 90 = 4n/2 [2n - 1]
➜ 90 = 2n [2n - 1]
➜ 4n² - 2n = 90
➜ 4n² - 2n - 90 = 0
➜ 2(2n² - n - 45) = 0
➜ 2n² - n - 45 = 0
➜ 2n² - 10n + 9n - 45 = 0
➜ 2n(n - 5) + 9(n - 5) = 0
➜ (n - 5) (2n + 9) = 0
➜ n = 5 (or) n = -9/2 (discarded)
➜ n = 5
Hence, n = 5
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