Question

In an AP a=4.d=3.S12=246 find a12 and a15

Answer 1

Answer:

a12=37 ; a15=46

Step-by-step explanation:

given, in an AP ,a=4 ,d=3

a12=a+(n-1)d

=4+(12-1)3

=4+(11)3

=4+33

=37

therefore,a12=37.

a15=a+(n-1)d

=4+(15-1)3

=4+(14)3

=4+42

=46

therefore,a15=46

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