in an AP a ratio of 5th and 10 th term is 1:2 and 12 th term is 36 find the AP
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in the explanation
Step-by-step explanation:
let the 5 th term be = a + 4d = x
and the 10 th term be = a + 9d = 2x
∴ (a+4d)/(a+9d) = 1/2
or, 2(a+4d) = (a+9d)
or, 2a + 8d = a + 9d where a = first term & d = common d
or, 2a - a = 9d - 8d d = common difference
or, a = d
∴12 th term is = a + 11d = 36
∴ d + 11d = 36
or, 12d = 36
or, d = 3
∴ a = d = 3
hence the AP is --------- 3,6,9,12,15,18,21,24,27,30,33,36,39................
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