in an ap a16=p,find the sum of first 31 terms
Answers
Answered by
9
T16 = P
Tn = a+(n-1)d
a + 15d = P --------------(1)
Sn = n/2[2a+(n-1)d]
S31 = (31/2) [2a+30d]
= (31/2) × 2 × (a+15d)
= 31 × (a+15d)
S31 = 31 P
=====================
Tn = a+(n-1)d
a + 15d = P --------------(1)
Sn = n/2[2a+(n-1)d]
S31 = (31/2) [2a+30d]
= (31/2) × 2 × (a+15d)
= 31 × (a+15d)
S31 = 31 P
=====================
Similar questions