in an AP an=3n+2 find the 12th term...?
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Ans=Sn=3n2-4n
S1=3-4=-1
S2=12-8=4
S3=27-12=15
A.P:-1,5,11,..........
a=-1 , d=6
a12=-1+(12-1)6
= -1+66
=65
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