In an AP consisting of 20 terms the 4th term is 29 and the Last term is 125. find the 10th term of the AP
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a20=125; a+19d=125-----(1)
a4=29; a+3d=29----(2)
(2)-(1)
a+3d=29
-(a+19d=125)
-16d= -96
d= -96/-16= 6
a+18= 29
a= 11
11+9*6= 11+54= 65= a10
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