Question

in an Ap correct relations Tn-5=Tn-4+d​

Answer 1

Answer:

0

Step-by-step explanation:

Tn -5 =Tn-4+d (1)

Tn -5 =Tn-4+d (1) Tn-Tn = 5-4+d

Tn -5 =Tn-4+d (1) Tn-Tn = 5-4+d= 1 +d

Tn -5 =Tn-4+d (1) Tn-Tn = 5-4+d= 1 +d-1=d

Tn -5 =Tn-4+d (1) Tn-Tn = 5-4+d= 1 +d-1=dputting d in equation (1)

Tn -5 =Tn-4+d (1) Tn-Tn = 5-4+d= 1 +d-1=dputting d in equation (1) Tn-5=Tn-4 + (-1)

Tn -5 =Tn-4+d (1) Tn-Tn = 5-4+d= 1 +d-1=dputting d in equation (1) Tn-5=Tn-4 + (-1)=5-4-1

Tn -5 =Tn-4+d (1) Tn-Tn = 5-4+d= 1 +d-1=dputting d in equation (1) Tn-5=Tn-4 + (-1)=5-4-1=0