Math, asked by rm2713852, 9 months ago

In an AP ,d = -2 ,n=5 and last term is 0 ,the value of a is​

Answers

Answered by rhythm1472
0

Answer:

an =0

d=-2

n=5

an=a+(n-1)d

0=a+(5-1) -2

0=a+(4)-2

0=a-8

a=8

Hope its clear

Answered by jaswasri2006
4

 \huge { \underbrace{ \red{ \sf \mathbb Given \:  \:  \:   \:   \sf\mathbb Data }}}

 \sf an = 0

 \sf d =  - 2

 \sf n = 5

 \blue{ \sf  a = ?} \bf{  \implies first \:  \:  \:  term}

 \\  \\  \\

 \sf 0 = \:  a  \: + (5 - 1)( - 2)

 \sf a \:  + (4)( - 2) = 0

 \sf a - 8 = 0

 \Large \boxed{ \boxed{ \green{ \bf First \: ter \: (a) = 8}}}

 \\  \\  \\  \\

Mark as Brainliest answer please my friend

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