Question

In an ap d=3 then t5-t7 is equal to

Answer 1

Answer:

-36

Step-by-step explanation:

Let a be the first term of an A.P. and common difference be.

so, t5-t17

t5=(a+4d)

t17=(a+16d)

therefore,

on subtracting t5-t17

(a+4d)-(a+16d)

a+4d-a-16d

4d-16d

-12d

-12x3  (d=3)

-36.

hope you like.

Answer 2

Answer:

the answer is -36

Step-by-step explanation:

I hope it helps u :)